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ARM: Avoid memcpy() in MurmurHash64A() if we are using 64 bit ARM.

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However note that in architectures supporting 64 bit unaligned
accesses memcpy(...,...,8) is likely translated to a simple
word memory movement anyway.
This commit is contained in:
Salvatore Sanfilippo 2017-02-19 14:59:39 +00:00
parent 1e272a6b52
commit 72d6d64771
3 changed files with 5 additions and 1 deletions
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1
src/Makefile
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@ -14,6 +14,7 @@
release_hdr := $(shell sh -c './mkreleasehdr.sh')
uname_S := $(shell sh -c 'uname -s 2>/dev/null || echo not')
uname_M := $(shell sh -c 'uname -m 2>/dev/null || echo not')
OPTIMIZATION?=-O2
DEPENDENCY_TARGETS=hiredis linenoise lua
NODEPS:=clean distclean

3
src/config.h
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@ -211,5 +211,8 @@ void setproctitle(const char *fmt, ...);
#if defined(__arm) && !defined(__arm__)
#define __arm__
#endif
#if defined (__aarch64__) && !defined(__arm64__)
#define __arm64__
#endif
#endif

2
src/hyperloglog.c
View File

@ -401,7 +401,7 @@ uint64_t MurmurHash64A (const void * key, int len, unsigned int seed) {
uint64_t k;
#if (BYTE_ORDER == LITTLE_ENDIAN)
#ifdef __arm__
#if defined(__arm__) && !defined(__arm64__)
memcpy(&k,data,sizeof(uint64_t));
#else
k = *((uint64_t*)data);